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49x^2+70x-24=0
a = 49; b = 70; c = -24;
Δ = b2-4ac
Δ = 702-4·49·(-24)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-98}{2*49}=\frac{-168}{98} =-1+5/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+98}{2*49}=\frac{28}{98} =2/7 $
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